Question

the first second and third terms of a proportion are 45, 6 and 15respectivelyfind the fourth term​

Answer 1

Given:-

• the first second and third terms of a proportion are 45, 6 and 15respectively find the fourth term.

To find:-

• The fourth term.

Solution:-

$\small\bold{Let \: the \: number \: be \: x}$

• $\small\bold{=>45x=6×15}$

• $\small\bold{=>x=90/45}$

• $\small\bold{=>x=2}$

hey mate! The fourth term is 2.

Explanation:-

• Hey mate! As we know that PRODUCT OF MEANS=PRODUCT OF EXTREMES.

• So on continuing with this rule we continue to find the 4th term by considering x as the 4th term.

• We also know that Means here stand for the the 2nd and 3rd term's product and Extremes stands for 1st and fourth term's product.

• So, for that as we know that 4th term we don't know ,hence, we will first find means and after that we look on the equation that 45×x is given.

• So as there is multiplication so when 45 goes to R.H.S. it changes to division form.

• And on dividing we get 2 as quotient hence , making it the 4th term.

Hope it helped!