Question

the first te of an AP is p and it's common difference is q find it's 10th term​

Answer 1

Answer:

a10=p+9q

here is ur ans.

Answer 2

Answer:

$t_{10}=p+9q$

Step-by-step explanation:

$we \ have \ formula\\\\t_{n}=a+(n-1)d\\\\where \ a \ is \ first \ term\\\\n \ number \ of \ term\\\\d \ is \ common \ difference\\\\putting \ value \ here\\\\t_{10}=p+(10-1)q\\\\t_{10}=p+9q$

Hope it is clear to you.