Question

the first term a and common difference d are given find first four terms of ap a=-1 d =-1/2​

Answer 1

Answer:

-1, -3/2, -2, -5/2

Step-by-step explanation:

a=t1=-1 and d=-1/2

so, a=t1=-1

t2=a+d=-1-1/2=-3/2

t3=a+2d=-1+2(-1/2)=-2

t4=a+3d=-1+3(-1/2)=-5/2

Answer 2

Step-by-step explanation:

$\color{lightgreen} \textbf{Given : }$

a = -1 , d = -1 /2 , n = 4

$\text{We \: \: know \: \: that,}$

$\large \color{lightgreen}an = a+ (n -1) d$

Substituting the given values,

n = 2,

=>a2 = -1 + 1(-1/2)

=> -1 -1/2 = -2 -1 / 2

a2 = - 3/ 2

Now a2 + d = a3

=> -3 / 2 - 1/ 2 = a3

=> a3 = -4 / 2

a3 = -2

Now a 3 + d = a4

=> -2 - 1/2 = a4

=> a4 = -4 -1 /2 = -8 -1/2

a4 = -9/2