the first term a and common difference d are given. find first four terms of A.P where a=-3, d=4
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Answer:
a=3,d=4
∴ First term=t
1
=a=3
Second term=t
2
=a+d=3+4=7
Third term=t
3
=a+2d=3+2×4=3+8=11
Fourth term=t
4
=a+3d=3+3×4=3+12=15
∴ the four terms of A.P are 3,7,11,15
Answered by
1
a = 3,d = 4
:. first term = t¹ = a = 3
Second term = t² = a+d = 3+4 = 7
Third term = t³ = a+2d = 3+2×4 = 3+8 = 11
Fourth term = t⁴ = a+3d = 3+3×4 = 3+12 = 15
:. The four terms of A.P are 3,7,11,15
Hope this helps you
gd morning anu
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