The first term & the last term of an arith
metic progression are a' & I respectively,
then the sum of its first n terms is
A) sn=n(2a+l)
B) sn = n(a+(n-1)d
C)sn= n(a+l)
D) sn = a(n+l)
Answers
Answered by
3
Step-by-step explanation:
The first term & the last term of an arith
metic progression are a' & I respectively,
then the sum of its first n terms is
A) sn=n(2a+l)
✍ ʜᴏᴘᴇ ɪᴛ's ʜᴇʟᴘғᴜʟ ᴛᴏ ʏᴏᴜ ✍
Answered by
3
Answer:
Step-by-step explanation:
answer is n/2(a+l)
the proof of snth formula is given in picture i hope you like it
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