Question

The first term and common difference of an A. P. are 12 and 14 respectively​

Answer 1

Step-by-step explanation:

AP : 12 , 26 , 40 , 54 , .... , 14n-2

$a = 12 \\ \\ d = 14 \\ \\ a(n) = a + (n - 1)d \\ \\ = 12 + (n - 1)(14) \\ \\ = 12 + 14n - 14 \\ \\ = 14n - 2.$

AP : 12 , 26 , 40 , 54 , .... , 14n-2 ✓