Question

The first term and last term of an ap are 17 and 350 respectively if the common difference is 9 how nany terms are there and what is their sum

Answer 1

a=17, an=350, D=9
an=a+(n-1)D
350=17+(n-1)9
(n-1)9=350-17
(n-1)9=333
(n-1)=333/9
n-1=37
n=37+1=38
thus, no. of terms=38
sum of ap=n/2[a+an]
=38/2(17+350)
=19×367
=6973

Answer 2

$\bf\huge\boxed{\boxed{\bf\huge\:Hello\:Mate}}}$

$\bf\huge Let\: a\: first\: terms\: and\: CD\: be\: D \:and\: L\: be\: last\: term$

$\bf\huge a = 17 , L = a_{n} = 350 and D = 9$

$\bf\huge According\:to\:the\:Question$

$\bf\huge => a_{n} = l = 350$

$\bf\huge => a + (n - 1)d = 350$

$\bf\huge => 17 + (n - 1)9 = 350$

$\bf\huge => 9(n - 1) => 350 - 17 = 333$

$\bf\huge => n - 1 = \frac{333}{9} = 37$

$\bf\huge => n = 37 + 1 = 38$

$\bf\huge Substitute\:a = 17 , l = 350 \:and\: n = 38$

$\bf\huge S_{n} = \frac{N}{n}(a + l)$

$\bf\huge S_{38} = \frac{38}{2}(17 + 350)$

$\bf\huge = 19\times 367$

$\bf\huge = 6973$

$\bf\huge\boxed{\boxed{\:Regards=\:Yash\:Raj}}}$