Question

The first term and last term of an ap are 5 and 45 respectively and the sum is 400 find the common difference​

Answer 1

Step-by-step explanation:

Step-by-step explanation:a = 5

Step-by-step explanation:a = 5An = 45

Step-by-step explanation:a = 5An = 45Sn= 400

Step-by-step explanation:a = 5An = 45Sn= 400

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/2

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)400/8= 10+15d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)400/8= 10+15d50=10+15d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)400/8= 10+15d50=10+15d50-40= 15d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)400/8= 10+15d50=10+15d50-40= 15d10/15=d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)400/8= 10+15d50=10+15d50-40= 15d10/15=d10/15=d

Step-by-step explanation:a = 5An = 45Sn= 400 Sn= n/2(a +An)400 = n/2(5 + 45)400=n/2(50)400/50=n/28=n/2n= 8*2n=16Sn= n/2(2a +(n-1)d400=16/2(2(5) +(16-1)d400=8(10+15d)400/8= 10+15d50=10+15d50-40= 15d10/15=d10/15=d2/3 = d

Answer 2

Answer:

8/3          

Step-by-step explanation:

a = 5; l = 45; d = ??; s = 400;

s = (n/2) * (a + l);

400 = (n/2) * (5 + 45);

400 = (n/2) * 50;

400 = n * 25;

n = 400/25;

n = 16;

l = a + (n - 1) * d;

45 = 5 + (16 - 1) * d;

45 - 5 = 15 * d;

40 = 15 * d;

d = 40/15;

d = 8/3;                .............(ans)