The first term and the common difference of an AP are 13 and 15 respectively find the sum from the sixth
term to the 20th term
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Answer:
a= 13. d=15
sn=n/2(2a+(n-1)d
s20=(20/2(2×13 +(20-1)×15)
=10(26+19×15)
=10(285)
=2850
S6=6/2(2×13+(6-1)×15
=303
sum from sixth term to the 20th term=s20-s6
=2850-303
=2547
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