The first term and the last term of an arithmetic progression are ‘a’ and ‘l’ respectively, then the sum of its first ‘n’ terms is
A. sn = n(2a+1)/2
B. sn = n(a+(n-1)d)/2
C. sn= n(a+l)/2
D. sn= a(n+l)/2
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Answer:
option d is your correct answer
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