Question

the first term, common difference and last term are 12,6,252,find the sum of all terms of ap​

Answer 1

Answer:

Hope this helps you

Step-by-step explanation:

a1=12

d=6

an=252

a+(n-1)d=252

12+(n-1)6=252

(n-1)6=252-12

(n-1)6=240

n-1=240/6

n-1=40

n=40+1

n=41

Sn=n/2 {a+an}

S41=41/2 (12+252)

=41/2 × 264

=41 × 132

=5412

Answer 2

Step-by-step explanation:

given,a=12,d=6,an=252

an=a+(n-1)D

252=12+(n-1)6

252-12=6n-6

240+6=6n

6n=246

n=246/6

n=41

now,sn=n/2 (a+an)

sn=41/2 (12+252)

sn=41/2×264

sn=5412.

hope this helps.

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