Question

The first term common difference and last term of an an Ap are 12,6 and 252 respectively, Find the sum of all terms of this AP

Answer 1

Answer:

5412

Step-by-step explanation:

a=12

d=6

a(n)=252

252=12+(n-1)6  ,using a(n) formula

252-12=(n-1)6

240/6=n-1

40+1=n

n=41

41/2(12+152)=s41

on solving it we get s41=5412