Question

the first term, common difference and the last term of an AP are 12,6 and 252respectively. find the number of terms​

Answer 1

Step-by-step explanation:

here,

a = 12

d = 6

an= 252

an = a+ (n-1) d

252= 12 + (n-1) 6

252 = 12+6n-6

252 = 6+6n

252- 6= 6n

246= 6n

246÷6 = n

41 = n

therefore, n means no of terms

a means first number

an means last number

d means common difference

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