The first term of a G.P 3 and its last term is 192 .Also the sum of the given series is 129 .find the number of term in the G.P.
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The first term of a G.P 3 and its last term is 192 .Also the sum of the given series is 129 .find the number of term in the G.P.
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keyurbhoj
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Answer: 7
Step-by-step explanation:
the GP can be written as a, ar, ar^2, ar^3...ar^(n-1)
now a=3 , ar^(n-1) = 192. taking ratio of both
ar^(n-1)/a = 192/3
r^(n-1)= 64 ......equation 1
now, sum = a* (r^n-1)/(r-1)
129 = 3* (64r-1)/(r-1) [ r^n = r*r^(n-1)=r*64=64r]
43 (r-1) = 64r - 1
43r - 43 = 64r -1
-21r=42
r = -2
now from equation 1
r^(n-1)= (-2)^(6)
n-1 = 6
n = 7
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