The first term of a G.P. is 1. The sum of third and fifth terms is 90. Find the common ratio of the G.P.
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a=1
3rd term=ar^2
5th term=ar^4
3rd +5th=ar^2(1+ar^2)=90
r^4+r^2-90=0
r^2=x
x^2+x-90=0
solving eq x=10,-9
r=+(10)^1/2
r=-(10)^1/2
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➠Question:-
The first term of a G.P. is 1. The sum of third and fifth terms is 90. Find the common ratio of the G.P.
➠Solution:-
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The first term of the given Geometric Progression a = 1.
Let ‘r’ be the common ratio of the Geometric Progression.
According to the problem,
⇒t3 + t5 = 90
⇒ar² + ar⁴ = 90
⇒r²+ r⁴ = 90
⇒r⁴ + r² – 90 = 0
⇒r² + 10r² - 9r² - 90 = 0
⇒(r² + 10)(r² - 9) =0
⇒r² - 9 = 0
⇒r² = 9
⇒r = ±3
Therefore, the common ratio of the Geometric Progression is -3 or 3.
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