Question

The first term of a geometric progression is 5/3 and the fourth term is 2/4. Find the common ratio​

Answer 1

Answer:

Let a be the first term and r be the common ratio of the given G.P.

Given that a=375,t4=192.

Now, tn=arn−1

Therefore, t4=375r3⇒375r3=192

⇒r3=375192⇒r3=12564

⇒r3=(54)3⇒r=54, which is the required common ratio.

Now, Sn=a[r−1rn−1] if r=1

Thus, S14=54−1275[(54)14−1]=(−1)×5×375[(