Question

the first term of A. P. is 1 and 12 th term is 45. Then its 8th term i​

Answer 1

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Step-by-step explanation:

a=1

n=12

an=45

an=a+(n-1)d

substituting value.

45=1+(12-1)d

45=1+11d

11d=45-1

d=44/11

d=4

8th term is

here n=8

a=1

d=4

an=the number in 8th term

an = a+(n-1)d

an=1+(8-1)4

an=1+7x4

an=1+28

an=29

so, 8th term is 29.