Question

The first term of an A.P is -1 and d=2 them 10th term is

Answer 1

Given :-

First term of A.P = -1

common difference (d) = 2

To find :-

10th term of the A.P

Formula used :-

Tn = a+(n-1)d

Solution :-

➡️Tₙ = a+(n-1)d

➡️T₁₀ = a+(n-1)d

➡️T₁₀ = -1+(10-1)2

➡️T₁₀ = -1+(9×2)

➡️T₁₀ = -1+ 18

➡️T₁₀ = 17

Answer :-

10th term of the A.P = 17

Answer 2

Answer:

Given :-

• The first term of an AP is - 1 and common difference is 2.

To Find :-

• What is the 10th term of an AP.

Formula Used :-

$\mapsto \sf\boxed{\bold{\pink{T_n =\: a + d(n - 1)}}}$

where,

• a = First term of an AP
• d = Common difference
• n = Number of terms

Solution :-

Given :

$\bigstar\: \: \rm{\bold{First\: term\: (a) =\: - 1}}$

$\bigstar\: \: \rm{\bold{Common\: difference\: (d) =\: 2}}$

$\bigstar\: \: \rm{\bold{Number\: of\: terms\: (n) =\: 10}}$

According to the question by using the formula we get,

$\longrightarrow \sf T_{10} =\: - 1 + 2(10 - 1)$

$\longrightarrow \sf T_{10} =\: - 1 + 2(10) - 2(1)$

$\longrightarrow \sf T_{10} =\: - 1 + 20 - 2$

$\longrightarrow \sf T_{10} =\: 19 - 2$

$\longrightarrow \sf\bold{\red{T_{10} =\: 17}}$

$\therefore$ The 10th term of an AP is 17.

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