the first term of an A.P. is 1 and the sum of first 15 terms is 225 find the common differences
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Answered by
8
first term of an AP is 1
so,a=1
and, Sum of 15 terms = 225
S15 = 225
15/2(2a+ (15-1)d)= 225
15/2(2+14d)=225
2+(14)d = 30
14d= 28
d= 2
Hence,common difference is 2
so,a=1
and, Sum of 15 terms = 225
S15 = 225
15/2(2a+ (15-1)d)= 225
15/2(2+14d)=225
2+(14)d = 30
14d= 28
d= 2
Hence,common difference is 2
Answered by
0
Step-by-step explanation:
a=1
s15=225
s15=(n/2)(2a+(n-1)d)
225=(15/2)(2(1)+(15-1)d)
225=(15/2)(2+14d)
225*2/15=2+14d
14d+2=450/15
14d+2=30
14d = 30-2
d=28/14
d=2
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