The first term of an A.P. is 3 and 11th tetm is 53.find S11.
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a1=3
a11=53
D=(a11-a1)/10=50-3/ 10=5
S11=11/2(3+53)=11*28=308
a11=53
D=(a11-a1)/10=50-3/ 10=5
S11=11/2(3+53)=11*28=308
Krishna461:
308 correct
yes thanks
welcome
Answered by
2
you can also use Sn=n/2 (a1+a11) formula. I just wanted to show you how to find difference.
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