The first term of an A.P. Is 4 and common difference is 4 If tn and Sn are the nth term and what is the sum of n term of A.P then
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According to AP formula
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Tn = a +(n-1)d___nth term
Sn = [2a + (n-1)d] n/2___sum of n terms
_______________________
Tn = 4 +(n-1)4 = 4n
Sn = n[2×4 + (n-1)4]/2
= [8-4 +4n]n/2 = (4+4n)n/2
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The relation between them is
Sn = (4+ Tn) n/2
-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
======================
Tn = a +(n-1)d___nth term
Sn = [2a + (n-1)d] n/2___sum of n terms
_______________________
Tn = 4 +(n-1)4 = 4n
Sn = n[2×4 + (n-1)4]/2
= [8-4 +4n]n/2 = (4+4n)n/2
----------------------------------------------
The relation between them is
Sn = (4+ Tn) n/2
-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
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