The first term of an a.p.is -4 and the 10th term id 14. Determ2 the 30th teem
Answers
Answered by
1
Hi mate !!
a ( First term ) :- ( - 4 )
d ( Common difference ) :- ?
n ( No. of term ) :- 30
an ( nth term ) :- ?
It is given that value of an when n = 10 is 14 i.e ,a10 = 14 !!
• an = a + ( n - 1 ) d .... ( i )
a10 = - 4 + 9d
14 = - 4 + 9d
14 + 4 = 9d
18 = 9d
2 = d
Now ,
Putting the value of n = 30 , d = 2 in Equation ( i )
a30 = ( - 4 ) + 29 × 2
a30 = - 4 + 58
a30 = 54
So, the 30th term of given AP is 54 !!
a ( First term ) :- ( - 4 )
d ( Common difference ) :- ?
n ( No. of term ) :- 30
an ( nth term ) :- ?
It is given that value of an when n = 10 is 14 i.e ,a10 = 14 !!
• an = a + ( n - 1 ) d .... ( i )
a10 = - 4 + 9d
14 = - 4 + 9d
14 + 4 = 9d
18 = 9d
2 = d
Now ,
Putting the value of n = 30 , d = 2 in Equation ( i )
a30 = ( - 4 ) + 29 × 2
a30 = - 4 + 58
a30 = 54
So, the 30th term of given AP is 54 !!
Answered by
0
Answer:
hyy
PLZ follow me
mark as branilist
Attachments:
Similar questions