The first term of an A.P. is 5 and its 100th term is -292. Find the 50th term of this A.P.(urgent)
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first term (a) = 5
common difference= (let it be d)
100 term = a+99d
-292 = 5+99d
d= -297/99
d= -3
50 th term = a+49d
= 5+(49*-3)
= 5-147
= -142
therefore 50th term is -142.
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