Question

the first term of an A.P is 5 and the Common
difference is 4. Find the sum of first 12 terms of the A.P a=5,d=4 ,S12=?
​

Answer 1

a = 5

d = 4

n = 12

Sum of terms = n/2[ 2a + (n-1)d]

= 12/2 [2x5 + (12-1)4]

= 6 [10 + 11x4]

= 6 [ 10 + 44 ]

= 6 x 54

= $\boxed{324}$

Hope it helps you❤

Answer 2

Answer:

mark the one as brainliest^_^