The first term of an A.P. is 5 and the common difference is 4. Find the sum of first 12 terms of the A.P. and also 19th term.
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Answer:
Step-by-step explanation:
Below in bold.
Step-by-step explanation:
Sum of n terms:
Sn = n/2[2a + (n-1)d] where a = first term and d = common difference, so:
S12 = 12/2[2*5 + (12-1)*4]
= 6 * 54
= 324.
19th term
= a + (19-1)d
= 5 + 18*4
= 77.
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