The first term of an A. P. is 5 and the common difference is 4. Complete
the following activity and find the sum of the first 12 terms of the A. P.
a = 5, d = 4, s12 = ?
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a=5,d=4
s12=n/2{2a+(n-1)d}
s12=12/2{10+11×4}
s12=6(10+44)
s12=6×54=324
s12=n/2{2a+(n-1)d}
s12=12/2{10+11×4}
s12=6(10+44)
s12=6×54=324
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