The first term of an A.P. is 5 and the common difference is 4. Complete the following activity and find the sum of the first 12 terms of the A.P. a=5,d=4,s¹²=?
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as it is activity based question you should send full question
sorry t12 is 49
So 6× 54
324
sorry t12 is 49
So 6× 54
324
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kaifchoudhary84:
Thank you so much sir
Answered by
5
a=5
d=4
sum of first n terms =n/2(2a+(n-1)d)
12/2(2*5+11*4)
6(10+44)
6×54
324
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