the first term of an A.P is 5 and the common difference is 10.complete the following activity to find the sum of first 10 terms of the A.P
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Answer-
The Sum of First Ten terms is 500.
Step by step explanation-
In context the the given question we have to find the value of first 10 terms on an A.P
Whose details are,
First term (a) = 5
Common Difference (d) = 10
No of terms = 10
As we know that,
Sum of an A.P = (n/2) x (2a+(n-1)d)
By putting the values,
We get,
Sum of an A.P = (10/2) x (2x5 + (10-1)10)
Sum of an A.P = 5 x ( 10 + (9)10)
Sum of an A.P = 5 x ( 10+90)
Sum of an A.P = 5 x 100
Sum of an A.P = 500.
Therefore; The Sum of First Ten terms is 500.
The Sum of First Ten terms is 500.
Step by step explanation-
In context the the given question we have to find the value of first 10 terms on an A.P
Whose details are,
First term (a) = 5
Common Difference (d) = 10
No of terms = 10
As we know that,
Sum of an A.P = (n/2) x (2a+(n-1)d)
By putting the values,
We get,
Sum of an A.P = (10/2) x (2x5 + (10-1)10)
Sum of an A.P = 5 x ( 10 + (9)10)
Sum of an A.P = 5 x ( 10+90)
Sum of an A.P = 5 x 100
Sum of an A.P = 500.
Therefore; The Sum of First Ten terms is 500.
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