Math, asked by aymantabassum, 5 months ago

The first term of an A.P is 5. the
2 points
last term is 45, & the sum is 400. The
number of terms & the common
difference respectively is:
a) 4 & 2/3
b) 2/3 & 4
c) 16 & 8/3
d) 8/3 & 16​

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
103

Answer

  • First term of an AP is 5
  • Last term = 45
  • Sum of all the terms = 400
  • Number of terms = ?
  • Common Difference = ?

━━━━━━━━━━━━━━

  • First we shall find the number 9f terms in the AP using the formula n/2 {a+l}. So then we shall substitute this in the formula to find the nth term which will give us the value of the common difference (d)

\sf :\implies s_n = \dfrac{n}{2} \bigg\lgroup First Term + Last Term \bigg\rgroup\\

\sf :\implies 400 = \dfrac{n}{2} \bigg\lgroup 5+45 \bigg\rgroup\\

\sf :\implies 400 = \dfrac{n}{2} \times 50 \\

\sf :\implies 400 = n\times 25\\

\sf :\implies \dfrac{400}{25} = n\\

:\implies \underline{\boxed{\red{\mathfrak{n = 16}}}}

  • Next substitute the given values in the formula to find the nth term to find the the value of common difference as we now have the value of a, n & aⁿ

\sf :\implies a_n = a+(n-1)d\\

\sf :\implies a_16 = a+(16-1)d\\

\sf :\implies 45 = 5+(15)d\\

\sf :\implies 45-5 = 15d\\

\sf :\implies 40 = 15d\\

\sf :\implies \dfrac{40}{15} = d\\

:\implies \underline{\boxed{\pink{\mathfrak{n = \dfrac{8}{3}}}}}

\displaystyle\therefore\:\underline{\textsf{The Answer is \textbf{Option C}}}


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Answered by Anonymous
115

Answer:

 \underline{ \sf{ \underline{☃Given:}}}

  • First term (a) = 5
  • Last term (l) = 45
  • Sum of terms (Sn) = 400

 \underline{ \sf{ \underline{☃Find:}}}

  • Number of terms?
  • Common difference?

 \underline{ \sf{ \underline{☃Solution:}}}

Number of terms:-

We know that

{ \boxed{ \sf{ s_{n} =  \frac{n}{2}(a  + l) }}}

{ \to{ \sf{400 =  \frac{n}{2}(5 + 45) }}}

{ \to{ \sf{400 =  \frac{n}{2}(50) }}}

{ \to{ \sf{400 = 25n}}}

{ \to{ \sf{n =  \frac{400}{25} }}}

{ \to{ \sf{n = 16}}}

So, Number of terms = 16

Common Difference:-

By using the formula

{ \boxed{ \sf{ s_{n} =  \frac{n}{2}(2a + n - 1)  d}}}

{ \to{ \sf{400 =  \frac{16}{2} (2 \times 5 + (16 - 1)d)}}}

{ \to{ \sf{400 = 8(10 + 15d)}}}

{ \to{ \sf{ \frac{400}{8}  = 10 + 15d}}}

{ \to{ \sf{50 = 10  + 15d}}}

{ \to{ \sf{50 - 10 = 15d}}}

{ \to{ \sf{15d = 40}}}

{ \to{ \sf{d =  \frac{40}{15}  =  \frac{8}{3} }}}

So, common difference = 8/3

Therefore,

Number of terms = 16

Common difference = 8/3

Step-by-step explanation:

"Option C is your answer"


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