the first term of an A. P is 5 ,the last term is 45 and the sum of their terms is 125.Find the number of terms?
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first term i.e, a=5
last term i.e, an=45
sum of all terms i.e, an=125
we can expand the last term as
a+(n-1)d=45
then sn=125
n/2*(a+a+(n-1)d)=125
n(5+45)=2*125
50n=250
n=5
The total no. of terms in the A.P is 5
I hope it will help you..
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