Question

The first term of an A.P. is 6 and the common difference is 3. Find S25.​

Answer 1

Answer:

hyyya ..

Step-by-step explanation:

since ,a=6 , d=3

we need to find S27=?

HERE, Sn=n/2{2a+{n-1}d}

               =27/2{2×6+{27-1}3}

               =27/2{12+26×3}

               =27/2{90}

               =27×45

                =1215

hence sum to 27 terms is 1215

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

ANSWER

Solution:

Given a=6d=3

S27=2n[2a+(n−1)d]

S27=227[2×6+26×3]

=227[12+78]

=227[90]

=1,215