Question

The first term of an A.P. is a and its common difference is d. If the ratio of sums of m
terms and n terms of the A.P. be m2:n2, then prove the d=2a.
Hint: See the hint for solving Question 22 of Exercise 11 (C).
31st term.​

Answer 1

Answer:

The ratio of the sums of m and n terms of an A.P is m2:n2. Show that the ratio of mth and nth term is (2m−1):(2n−1).

Step-by-step explanation:

Answer 2

Answer:

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