Question

the first term of an A.P.of 20 terms is 2 and its last term is 59. Find its 6th term from the end

Answer 1

a= 2
a+19d = 59
d= (59-2)/19=3

sixth term from end = last term - 5d
= 59 -5×3 = 59-15= 44

Thats your answer!
check for any calculation mistakes.

Answer 2

Answer:

$</p><p>6^{th}\: term \: from \: \\end \: of \: the \: A P\:= 44$

Step-by-step explanation:

Given First term in an A.P (a)=2

number of terms (n)=20,

Last term (l) = 59

Let common difference = d

$last\:term = a+(n-1)d=l$

$\implies 2+(20-1)d=59$

$\implies 2+19d=59$

$\implies 19d=59-2$

$\implies 19d=57$

$\implies d=\frac{57}{19}$

$\implies d = 3$

$Now, \\</p><p>6^{th}\: term \: from \: \\end \: of \: the \: A P\:\\a_{6}= l+(n-1)(-d)\\=59+(6-1)(-3)\\=59+5\times (-3)\\=59-15\\=44$

Therefore,.

$</p><p>6^{th}\: term \: from \: \\end \: of \: the \: A P\:= 44$

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