The first term of an AP is 10. The last term is 50. If the sum of all the terms is 480. Find the common difference and the number of terms
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First term, a1 = 10
Last term, an = 50
Sum of all the terms = 480
Find the number of terms:
Sn = n/2 (a1 + an)
480 = n/2 (10 + 50)
480 = n/2(60)
480 = 30n
n = 480 ÷ 30
n = 16
Find the common difference:
an = a1 + (n - 1)d
50 = 10 + (16 - 1)d
50 = 10 + 15d
15d = 40
d = 8/3
Answer: There are 16 terms and the common difference is 8/3
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