Question

The first term of an ap is 2 and common difference is 4 .The sum

Answer 1

Hi there,

as here number of terms is not given so assuming number of terms is 40

(if n is other than 40 u can replace 40 with the actual value of n)

SO

Here,

a=2

d=4 and n=40

as we know, Sn=n/2(2a+(n-1)d)

S40=40/2(2*2+(40–1)4)

=20(4+156)

=20*160

=3200

____________________________________________

Hope It Helps

Best of Luck

Please Mark My Answer as Brainliest Answer