Question

The first term of an ap is 2 and last term is 50 the sum of all these terms is 442 find the common difference.

Answer 1

Given:-

first term, a = 2

last term , l = 50

let,

total no. of terms in AP = n

then,

sum of all terms, Sₙ = 442

To find:-

common difference, d  =  ?

Solution:-

Sₙ = n/2 ( a + l )

442 = n/2 ( 2 + 50 )

442 * 2 / 52  = n

n = 17

now,

l = a + ( n - 1 ) d

50 = 2 + ( 17 - 1 ) d

50 - 2 = 16 d

d = 3 .

common difference of the AP will be 3 .