the first term of an ap is 22 and the common difference is 3 then 49th term is
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Firts term =a=22
Common difference d==−4
Sum =S=64
S=2n(a+a+(n−1)d)
S=2n(2a+(n−1)d)
64=2n(44+(n−1)(−4))
128=n(44−4n+4)
128=n(48−4n)
128=48n−4n2
4n2−48n+128=0
n2−12n+32=0
n=2+12±122−4×32
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Step-by-step explanation:
49th term is 166.
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