Question

The first term of an AP is – 3 and 12th term is 41. Determine the common
difference.

Answer 1

Answer:

The common difference, d = 4

Explanation:-

Given:-

• The first term of an AP $a_1$ is – 3
• 12th term = 41

We are asked to find out the common difference of the given AP respectively.

So,

Let's proceed!!

• $a_1 = - 3$
• 12th term = 41
• d = ?

We know that,

$a_n$ = $a_1 + ( n - 1)d$

$\implies$ $a_1 + ( 12 - 1)d$ = $a_12$

$\implies$ - 3 + 11d = 41

$\implies$ 11d = 41 + 3

$\implies$ 11d = 44

$\implies$ d = $\large\frac{\cancel{44}}{\cancel{11}}$

$\boxed{ d = 4 }$