Question

The first term of an AP is -4 and the 10th term is 14 . Determine the 30th term.

Answer 1

Answer:

the 30th term is 370/9 = 41.11. please mark as brainlist and follow

Answer 2

Answer:

The 30th term of the A.P. is 54.

Step-by-step explanation:

Given, First term, a = -4

          10th term, $a_{10}$ = 14.

We know that, $a_{n} = a + (n-1)d$

To find common difference;

$a_{10} = a + (10 - 1)d$

14 = - 4 + 9d

9d = 14 + 4

d = $\frac{18}{9}$ = 2.

Hence, common difference of the given A.P. is 2.

To find 30th term;

Again, we know

$a_{n} = a + (n-1)d$

$a_{30} = a + (30 - 1) d$

$a_{30}$ = - 4 + 29 (2)

$a_{30}$ = -4 + 58 = 54.

The 30th term of the A.P. is 54.

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