the first term of an ap is 5 and common difference is 4 complete the following activity to find the sum of the first 12th term of the AP
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a=5, d =4 sn ?
sn=n/2(2a+(n-1)d)
s12= 12/2(2*5+(12-1)4)
=6(10+(11)4)
=6(10+44)
=6(54)
=324
therefore, the sum of the first 12th term of an AP is 324
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