The first term of an ap is -5 and last term is 45. If the sum of the terms is 120, then find the number of terms .
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Now, (a1) = -5
(an) = 45
Sum = 120
Sum of AP = (n/2)[(a1)+(an)]
120 = (n/2)(-5+45)
120*2=(n/2)(40)
(240/40)=n
n=6
Number of terms in the AP is 6.
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