Question

the first term of an ap is 5 and the common difference is 4 find the sum of the first 12 term of the AP ​

Answer 1

Answer:

Given

a = 5 , d = 4

then

• S12 = 12/2 x ( 2x5 + 11x 4)
• = 6x ( 10 + 44 )
• = 6 x 54
• =
• $6 \times54$
• 324....

Hope this helps ...

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Answer 2

≡QUESTION≡

The first term of an A.P. is 5 and the common difference is 4. Find the sum of the first 12 terms of the AP .

                                                                                                 

║⊕ANSWER⊕║

GIVEN

a = 5

d=4

n= 12

SOMETHING YOU SHOULD KNOW FIRST

Formula =  Sₙ=n/2 (2a+(n-1)d) is used to find the sum of "n'' numbers.

SOLUTION

S₁₂=12/2(2×5+(12-1)4)

    =6 (10+44)

   = 6×54

Sₙ= 324

∴The sum of the first 12 terms = 324