The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms
and the common difference.
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first term a=5, last term l=45 and Sn = 400
Since, Sn=2n(a+l)
⇒400=2n(5+45)
⇒400=2n(50)
⇒400=n(25)
⇒n=16
Since, l=a+(n−1)d
⇒45=5+(16−1)d
⇒45−5=(15)d
⇒40=15d
⇒d=1540
⇒d=38
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