The first term of an AP of
consecutive integers is p2 + 1. The
sum of 2p + 1 terms of this AP is
(p + 1)2
(2p + 1) (p + 1)2
(p+1)3
p3 + (p + 1)3
Answers
Answered by
2
Answer:
a=k
2
+1
Since series is of consecutive integer
Sum of (2k+1) terms =
2
n
(2a+(n−1)d)
=
2
(2k+1)
[2(k
2
+1)+(2k+1−1)1]
=
2
(2k+1)
[2k
2
+2+2k]
=(2k+1)(k
2
+k+1)
=2k
3
+2k
2
+2k+k
2
+k+1
=k
3
+k
3
+1+3k
2
+3k
=k
3
+(k+1)
3
Step-by-step explanation:
hope it helpful for you
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