The first term of an arithmetic progression is 18 and the twelfth term is 46.Find the 18th term of the series??
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Answer:
a=18
a12=46
a18= ?
ans = an=a+(n-1)d
a12= 18+(12-1)d
now putting a12 is 46
46=18+11d
46-18=11d
28/11= d
now,
a18 = 18 + 17d
=18+17×28/11
=674/11 ans
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