Question

The first term of an arithmetic progression is 22 and the last term is -11. If the sum is 66, the number of terms in the sequence are?

Answer 1

Answer:

n=12

Step-by-step explanation:

n/2(a+l)=66

n/2(22+(-11) )=66

n/2(11)=66

n/2=6

n=12