Question

The first term of an arithmetic sequence is 1 and the sum of the first four terms is 100. Find the 1st four terms

Answer 1

Answer:

Given that,

First term of A.S = 1,

In general we consider a as the first term,

So, Let a = 1,

Let the next other 3 terms be , b,c,d

According to the Question,

a + b + c + d = 100,

We know the Formula for Sum of n terms of Arthimetic Sequence,

Sn(Sum of n terms) = (n/2)(a+l)

Where a = first term, l = last term, n = no.of terms,

=> 100 = (4/2)(1 + l)

=> 50 = 1 + l,

=> l = 49,

Now, We have to find Common difference(d),

Nth term of A.P = a + (n-1)*d,

=> 49 = 1 + 3*d,

=> 48 = 3d,

=> 16 = d,

=> b = 1 + 16 = 17,

=> c = 17 + 16 = 33,

=> d = 33 + 16 = 49 ✔(This is what we got before)

Therefore : First 4 terms of the A.P are 1 , 17 , 33 , 49 ,

Step-by-step explanation:

Answer 2

Answer:

1,17,33,49

Step-by-step explanation:

this is absolutely answer