The first term of an arithmetic sequence is 10 and the third term
is 24 ,
what is its common difference and find its 10th term ?
Answers
Answer:
common difference is 7.5 and the 10th term is 77.5
Step-by-step explanation:
first find the mid term between 10 and 24
10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
it is 17.5
now find the nth term for the sequence which is
7.5n + 2.5
now substitute 10 in the place of n
7.5 * 10 + 2.5
= 75 + 2.5
= 77.5
Answer:
First term of the sequence is 10 and common difference is 3.
a
1
= 10 and d = 3
Next term = a
2
=a
1
+d=10+3=13
a
3
=a
2
+d=13+3=16
Thus, first three terms of the sequence are 10, 13 and 16.
Let 100 be the nth term of the sequence.
a
n
=a
1
+(n−1)d
100=10+(n−1)3
90=(n−1)3
n−1=30
n=31, which is a whole number.
Therefore, 100 is the 31
st
term of the sequence.
Step-by-step explanation:
First term of the sequence is 10 and common difference is 3.
a
1
= 10 and d = 3
Next term = a
2
=a
1
+d=10+3=13
a
3
=a
2
+d=13+3=16
Thus, first three terms of the sequence are 10, 13 and 16.
Let 100 be the nth term of the sequence.
a
n
=a
1
+(n−1)d
100=10+(n−1)3
90=(n−1)3
n−1=30
n=31, which is a whole number.
Therefore, 100 is the 31
st
term of the sequence.