Question

The first term of an arithmetic sequence is 5 and the common differenced is 2.T₁₀ =

Answer 1

Answer:

a10 = 23

Step-by-step explanation:

a1 = 5

d=2

a10= a1+9d

a10 = 5+9*2=23

Answer 2

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The first term of AP is -5 and second term means -3. 

Common difference(d) = second term - first term

d = (-3)-(-5)

d= 2

Now using the formula of nth Tn=a1+(n−1)d

Here a1=−5,n=50,d=2

Puting these values in the formula of of nth term we get 

an=−5+(50−1)2

an=−5+98

an=93