The first term of an arithmetic sequence is 6 and common difference is 4.what is the algebraic expression to find the sum of the first n terms of this sequence?
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Answer:
2 n² + 4 n
Step-by-step explanation:
Given :
First term = 6
Common difference = 4
We know :
S_n = n / 2 [ 2 a + ( n - 1 ) d ]
S_n = n / 2 [ 12 + 4 ( n -1 ) ]
S_n = n [ 6 + 2 ( n - 1 ) ]
S_n = n ( 2 n + 4 )
S_n = 2 n² + 4 n
Therefore , sum of the first n terms of this sequence in algebraic expression as 2 n² + 4 n .
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